(x-1)(x^2+x+1)=0

Solution for (x-1)(x^2+x+1)=0 equation:

Simplifying
(x + -1)(x2 + x + 1) = 0

Reorder the terms:
(-1 + x)(x2 + x + 1) = 0

Reorder the terms:
(-1 + x)(1 + x + x2) = 0

Multiply (-1 + x) * (1 + x + x2)
(-1(1 + x + x2) + x(1 + x + x2)) = 0
((1 * -1 + x * -1 + x2 * -1) + x(1 + x + x2)) = 0
((-1 + -1x + -1x2) + x(1 + x + x2)) = 0
(-1 + -1x + -1x2 + (1 * x + x * x + x2 * x)) = 0
(-1 + -1x + -1x2 + (1x + x2 + x3)) = 0

Reorder the terms:
(-1 + -1x + 1x + -1x2 + x2 + x3) = 0

Combine like terms: -1x + 1x = 0
(-1 + 0 + -1x2 + x2 + x3) = 0
(-1 + -1x2 + x2 + x3) = 0

Combine like terms: -1x2 + x2 = 0
(-1 + 0 + x3) = 0
(-1 + x3) = 0

Solving
-1 + x3 = 0

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '1' to each side of the equation.
-1 + 1 + x3 = 0 + 1

Combine like terms: -1 + 1 = 0
0 + x3 = 0 + 1
x3 = 0 + 1

Combine like terms: 0 + 1 = 1
x3 = 1

Simplifying
x3 = 1

Reorder the terms:
-1 + x3 = 1 + -1

Combine like terms: 1 + -1 = 0
-1 + x3 = 0

The solution to this equation could not be determined.